19x^2-13x-12=0

Solution for 19x^2-13x-12=0 equation:

19x^2-13x-12=0

a = 19; b = -13; c = -12;
Δ = b2-4ac
Δ = -132-4·19·(-12)
Δ = 1081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{1081}}{2*19}=\frac{13-\sqrt{1081}}{38}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{1081}}{2*19}=\frac{13+\sqrt{1081}}{38}
$